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Organic bond polarity

The more electronegative atom of a bond is its δ− end: carbon is δ+ next to oxygen, nitrogen or a halogen, nearly neutral next to hydrogen, and δ− next to a metal, and the δ+ carbon is where nucleophiles attack.

Paper packet. Every task here also exists on screen, where it is checked automatically; answers written on paper are not assessed by Nydus. When you are back at a device, enter your answers there.

1. What you will learn

You will calculate electronegativity differences, say which end of a bond is δ+, rank bonds by polarity, and predict how a reversed carbon polarity changes reactivity.

2. What you already have

Formal charge assumes every bond is shared evenly. Most bonds are not: one atom pulls harder. Polarity is the partial charge that results, and unlike formal charge it describes where the electron density really is.

3. Words for this lesson

Electronegativity is how strongly an atom pulls a shared pair; on the Pauling scale carbon is 2.55. A polar bond shares its pair unevenly; the atom with the larger share is δ− (partial negative), the other δ+. An electrophilic site is electron-poor; a nucleophilic one, electron-rich.

4. Compare with carbon's 2.55

Pauling electronegativities of the atoms carbon usually bonds to:

AtomFOClNBrCHMgLi
Value3.983.443.163.042.962.552.201.310.98

Anything to the left of carbon pulls the pair away from it: in C–O, C–N and C–Cl, carbon is δ+. Hydrogen and carbon itself are close enough that C–H and C–C are treated as nearly nonpolar. Metals are far to the right, so in C–Li and C–Mg the carbon is δ−.

The size of the difference says how polar: C–O at 0.89 is strongly polar, C–N at 0.49 moderately, C–H at 0.35 barely.

Another way: steps

For any bond:

  1. Look up both electronegativities.
  2. The larger is δ−, the smaller δ+.
  3. The difference says how polar.
  4. A δ+ carbon is an electrophilic site; a δ− carbon, a nucleophilic one.

5. Polarity points to reactivity

A δ+ carbon is short of electrons and attracts electron-rich reagents: the carbon of a C=O or a C–Cl is where a nucleophile attacks (units 5 and 7). A δ− carbon, as in a Grignard reagent CH3MgBr, is itself electron-rich and seeks out δ+ carbon — which is how chemists make new carbon–carbon bonds. Reversing a carbon's polarity by bonding it to a metal is one of organic chemistry's most useful tricks.

A molecule's overall polarity is a separate question: in tetrachloromethane, CCl4, four polar C–Cl bonds point to the corners of a tetrahedron and cancel, so the molecule has no dipole, though every bond is polar.

6. Where this goes wrong

Every bond to carbon is nonpolar. Only C–H and C–C are nearly so.

Carbon is always the positive end. Next to a metal it is the negative end.

The larger atom is the negative end. Electronegativity decides, not size.

A molecule with polar bonds is always polar. Bond dipoles can cancel.

7. The C=O of methanal

  1. Oxygen 3.44, carbon 2.55: a difference of 0.89.

    Strongly polar.

  2. Oxygen is δ−, carbon δ+.

    Oxygen takes the larger share.

  3. So the carbonyl carbon is the electrophilic site a nucleophile attacks.

    Polarity points to reactivity.

8. Your turn: methyllithium, CH3Li

  1. Lithium 0.98, carbon 2.55. Which is δ−?

    Carbon.

  2. So is the CH3 carbon electrophilic or nucleophilic?

  3. Your turn: work this step out. Its working is at the end of the packet.

    Nucleophilic: electron-rich, like a Grignard carbon.

9. Guided practice

Carbon's Pauling electronegativity is 2.55 and nitrogen's is $3.04$. What is the electronegativity difference across the C–N bond?

Answer:

10. Guided practice

In a C–O bond, oxygen has electronegativity $3.44$ and carbon $2.55$. Which statement describes the bond?

11. Practice

Match each bond to the partial charge on its carbon. (Electronegativities: C 2.55, H 2.20, O 3.44, Cl 3.16, Li 0.98.)

δ+δ−almost no partial charge
the carbon of a C–O bond
the carbon of a C–Cl bond
the carbon of a C–Li bond
the carbon of a C–H bond

12. Practice

Rank these bonds from most polar to least polar. (Electronegativities: C 2.55, H 2.20, N 3.04, O 3.44, F 3.98.)

Number the steps in order (write the number in the box):

13. Somewhere new

A Grignard reagent, CH3MgBr, is added to propanone, (CH3)2C=O. Magnesium's electronegativity is 1.31 and carbon's 2.55. Which atom of the Grignard reagent seeks out the carbonyl carbon?

14. Lesson test

Lesson test: one question per skill, one attempt each, no hints. Your answers are checked when you submit.

15. Test question

For each bond in chloromethanol, ClCH2OH, name the atom at its δ+ end. (Electronegativities: H 2.20, C 2.55, O 3.44, Cl 3.16.)

atom at the δ+ end
C–Cl
C–O
O–H
C–H

16. What you can do now

You can read where a bond is short of electrons. Tell someone why the carbon of a Grignard reagent is δ−. Next: putting charge, resonance and polarity together to find a molecule's reactive site.

Working for the steps left to you

8. Your turn: methyllithium, CH3Li, step 3