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Reading the cost off the frontier

Turning a move along a frontier into a rate, in both directions, and why on a straight line one rate describes the whole of it.

Paper packet. Every task here also exists on screen, where it is checked automatically; answers written on paper are not assessed by Nydus. When you are back at a device, enter your answers there.

1. What you will learn

You will read the opportunity cost of either good straight off a production possibility frontier, by dividing the whole drop in one good by the whole gain in the other. You will be able to give the rate in both directions, check that the two multiply to one, and say why on a straight frontier the rate is the same at every point.

2. Starting point

Use the stated alternatives, quantities and units. Separate a model's assumptions from the conclusion derived from them.

3. Terms to use precisely

TermWhat it means
Output gainEnding quantity minus starting quantity for the good increased.
Output forgoneThe positive reduction in the alternative good.
Opportunity-cost rateAlternative output forgone per unit of the output gained.
Signed slopeVertical change divided by horizontal change, including its sign.
Average interval costThe total sacrifice divided by the total gain across a specified movement.

4. Read a change, not a point's coordinates alone

The opportunity cost of increasing one output along an efficient production frontier is the quantity of the other output forgone. To calculate a rate, identify a starting combination and an ending combination. If A rises from two to five while B falls from sixteen to ten, the producer gains three A and gives up six B. Dividing six by three gives two B forgone per additional A over that movement.

The starting point matters. Dividing the ending B coordinate by the ending A coordinate would give ten divided by five, which happens to equal two in this example but is not the general method. Those coordinates describe an output mix, not the changes between plans. A different starting point or ending coordinate could expose the error. Always calculate the output changes explicitly before dividing.

Use a consistent axis convention. With A horizontal and B vertical, a move to more A along a downward-sloping frontier has a positive horizontal change and a negative vertical change. The signed slope is change in B divided by change in A. The opportunity cost of A expressed in B is usually reported as the positive quantity of B forgone per A gained. Keeping these two descriptions separate prevents a sign convention from obscuring the economic meaning.

The comparison assumes that the points belong to the same relevant production frontier under unchanged resources and technology. Comparing unrelated points from different dates or different capacity models does not automatically measure a movement along one frontier. A new resource stock can permit both outputs to rise. That situation is a change in possibilities rather than the same trade-off represented by two points on an unchanged boundary.

Another way: Subtract first, then divide in the requested direction

Calculate A gained as ending A minus starting A. Calculate B forgone as starting B minus ending B when B falls. Both magnitudes are positive for the movement considered here. The rate in B per A is B forgone divided by A gained. Write the unit before entering the number so the numerator and denominator follow the question rather than the visual size of the coordinates.

Suppose a movement goes from (1,15) to (4,9). A rises by three and B falls by six, so the rate is six divided by three, or two B per A. The full movement costs six B; one additional A costs two B at this rate. The total quantity forgone and the per-unit opportunity cost answer different questions. If a prompt asks for the cost of three additional A, do not report only the per-unit rate without scaling it.

The reverse comparison has reciprocal units. Over the same straight segment, obtaining one more B requires giving up half an A. That is three A divided by six B, or 0.5 A per B. Two B per A and 0.5 A per B describe the same trade-off in opposite directions. They are not rival estimates of one unlabeled quantity. A correct response needs the correct direction.

Neither division rule says to put the larger number on top. If four A are gained while one B is forgone, the cost is 0.25 B per A. A rate below one is perfectly meaningful. Automatically inverting it would answer the cost of B in A units. The lesson on relative prices taught the same discipline: the requested good and alternative determine the ratio, not a habit of avoiding fractions.

Another way: Connect the rate to a resource account

In a constant-productivity model, the opportunity-cost rate can also be derived from per-unit resource requirements. If A uses four hours and B uses two, shifting four hours to one A sacrifices two B. The rate is four divided by two, or two B per A. This agrees with the slope obtained from any two distinct points on the resulting straight frontier.

The total resource stock determines the intercepts but does not by itself determine the per-unit trade-off when the production rates remain unchanged. Doubling available hours can double both single-good maxima while preserving the ratio of hours per A to hours per B. The expanded frontier is farther out, yet its straight-line slope can be the same. Distinguish the size of the feasible set from the relative cost of one output.

Changing the productivity of only one activity can alter the rate. If A's requirement falls from four hours to two while B still requires two, one A now costs one B rather than two. The alternative resources forgone have changed. This result follows from the new technology assumption; it is not inferred merely because one observed production point moved.

Use the resource account as an independent check when the problem supplies it. A coordinate calculation yielding three B per A would be inconsistent with the unchanged four-hours-versus-two-hours technology. The disagreement would signal a wrong subtraction, reversed coordinate, or point that does not belong to the claimed frontier. Cross-checking representations helps diagnose errors instead of just repeating the same arithmetic twice.

Another way: A curved frontier can have different interval costs

A straight frontier has a constant slope, so the per-unit opportunity cost is the same across its segments. A curved or piecewise frontier need not. For example, moving from (0,12) to (2,10) gains two A and loses two B, giving one B per A. Moving from (2,10) to (4,6) gains two A and loses four B, giving two B per A. The second movement has a larger cost for the same gain in A.

One reason is that resources differ in their suitability for tasks. Early transfers toward A may use resources that give up relatively little B, while later transfers sacrifice more B. The numerical table alone establishes the changing rates across the supplied segments. Explaining why the actual technology has that pattern requires further evidence or an explicit model of resource differences.

A rate calculated between distant points on a curved frontier is an average over that movement. From (0,12) to (4,6), six B are forgone for four A, an average of 1.5 B per A. That average does not equal either segment's rate in the example. Do not announce it as the cost of every individual A along the path. A smaller interval or more detailed model may be needed for a local marginal cost.

At this level, the scored tasks state whether a segment is straight or ask only for the average rate between the supplied points. We do not infer a derivative from two arbitrary observations. This keeps the arithmetic aligned with the available information and prepares for later work on changing opportunity costs without pretending that every frontier can be summarized by one permanent ratio.

Another way: Check interpretation as carefully as arithmetic

First check that the movement actually gains the good named in the question. If A does not change, dividing by its gain would involve zero and would not produce a finite B-per-A rate. If both goods rise because an initial point was inefficient, the movement is not a standard opportunity-cost trade-off along an unchanged efficient frontier. The question's assumptions should identify a suitable comparison before the formula is applied.

Next distinguish the signed slope from the positive cost magnitude. A signed slope of negative two means B falls by two units when A rises by one along the straight frontier. Reporting an opportunity cost of two B per A captures the forgone quantity. A negative sign is appropriate when the task explicitly asks for the signed slope. The two answers are compatible because they label different mathematical descriptions.

Then check units and scale. A graph with B measured in dozens and A measured in individual units has a different numerical rate from one with both goods measured individually. Converting B dozens into B units multiplies the numerical cost by twelve. This is not a change in production possibilities; it is a change in measurement. The units belong in the explanation, especially when comparing graphs.

Finally limit the conclusion. A production opportunity cost does not automatically equal a market price or establish which mix society should choose. Prices, preferences, distribution, and institutions require additional analysis. This lesson determines the production sacrifice under a stated model. That clear and bounded result is useful precisely because it does not pretend to answer every economic question at once.

5. Reallocating a print workshop's capacity

A fictional print workshop can produce either poster batches A or booklet batches B using the same fixed machine capacity. Two points on a straight efficient frontier are (2,18) and (6,10). The first coordinate is A and the second B, with both outputs measured in batches per afternoon. Moving to the second point gains four poster batches and gives up eight booklet batches.

The opportunity-cost rate is eight divided by four, or two booklet batches per poster batch. The signed slope on an A-horizontal, B-vertical graph is negative two. The complete four-poster increase costs eight booklets, while the per-poster rate is two. These are three compatible descriptions: a total sacrifice, a positive per-unit cost, and a signed graph slope.

The manager asks for the reverse rate. Along the same straight segment, gaining one booklet batch requires giving up 0.5 poster batches in the divisible-output model. The reciprocal calculation uses four divided by eight. Writing 'two' for both directions would confuse units and imply an inconsistent trade-off.

Now imagine that the workshop's next segment has a different rate because the remaining equipment is less suited to posters. The original two-booklet rate remains valid for the stated segment but need not apply beyond it. The manager should use the new segment's quantities rather than extrapolate an old slope without checking the technology. The exercise illustrates how explicit endpoints, units, and the straight-segment assumption make a production comparison precise and keep its limits visible.

6. Check the tempting inference

Use differences between endpoints, not a ratio of one point's coordinates. State which good is gained and which is forgone. Signed slope and positive opportunity-cost magnitude differ by sign in the standard downward case. A distant-point average on a curved frontier is not automatically the local marginal cost or a market price.

7. Calculate a rate from two points

  1. Record the same-frontier endpoints.

    Start(1,15); end(4,9)

    A is first and B second at both points.

  2. Find the A increase.

    4-1=3 A

    The gain is a difference, not the ending coordinate.

  3. Find the B sacrifice.

    15-9=6 B

    The forgone quantity is reported as a positive magnitude.

  4. Calculate the per-unit cost.

    6/3=2 B per A

    Divide alternative output lost by output gained.

  5. Check the full movement.

    3 A x 2 B per A = 6 B

    The per-unit rate recovers the total sacrifice.

8. Read the reverse direction

  1. Keep the same output changes.

    3 A correspond to 6 B

    The two quantities describe one straight segment.

  2. Name the requested reverse unit.

    A per B

    This reverses numerator and denominator.

  3. Divide in the new direction.

    3/6=0.5 A per B

    A rate below one is meaningful.

  4. Check reciprocal consistency.

    2 x 0.5=1

    The rates undo one another under the same units.

  5. Separate the signed slope.

    Signed B/A slope=-2

    A falling B coordinate introduces the negative graph sign, not a negative sacrifice magnitude.

9. Different segments have different costs

  1. Read three frontier points.

    (0,12),(2,10),(4,6)

    They are supplied efficient combinations of the same model.

  2. Calculate the first segment's changes.

    A gain 2; B loss 2

    The first movement has equal numerical changes.

  3. Compute its rate.

    2/2=1 B per A

    This rate belongs to the first segment.

  4. Calculate the second segment's changes.

    A gain 2; B loss 4

    The same A gain now sacrifices more B.

  5. Compute its different rate.

    4/2=2 B per A

    A single constant slope cannot describe both segments.

  6. Check the full-interval average.

    6/4=1.5 B per A

    An average over the whole move is not each segment's cost.

10. Finish a directional slope check

  1. A straight-frontier move goes from (2,14) to (6,6).

    A gain 4; B loss 8

    The resource stock and technology remain fixed.

  2. Compute B per A.

    8/4=2

    B is the alternative forgone.

  3. Your turn: work this step out. Its working is at the end of the packet.

    Reverse the unit carefully.

11. Guided practice

On a straight efficient frontier, move from (A,B)=(1,18) to (5,10). Give B per A and the reciprocal A per B.

Your result
B forgone per A gained
A forgone per B gained

12. Guided practice

A straight-frontier movement goes from (A,B)=(1,11) to (3,7). Complete the rate calculation.

  1. Calculate the increase in horizontal output.

    gain

    Subtract the initial first coordinate from the final first coordinate.

  2. Calculate the positive alternative output forgone.

    loss

    Subtract the final second coordinate from its initial value.

  3. Divide sacrifice by gain.

    rate B per A

    The requested unit determines the order of division.

13. Guided practice

A straight-frontier move goes from (0,8) to (4,6). Give B forgone per A gained and the reciprocal A per B; fractional rates are allowed.

B forgone per A gained: v0. A forgone per B gained: v1.

14. Practice

Along a straight efficient frontier, (A,B) moves from (2,20) to (6,8). Produce the positive opportunity-cost rate in B units per additional A.

Answer:

15. Practice

A stated frontier interval runs from (A,B)=(3,17) to (7,15). Give the average B-per-A rate over this interval and its reciprocal, without claiming either is the cost at every intermediate point.

B forgone per A gained: v0. A forgone per B gained: v1.

16. Somewhere new

A fictional print shop moves along a straight efficient frontier from (poster batches A, booklet batches B)=(2,18) to (6,10). Give booklets forgone per poster gained and the reciprocal poster-per-booklet rate.

B forgone per A gained: v0. A forgone per B gained: v1.

17. Lesson test

Lesson test: one question per skill, one attempt each, no hints. Your answers are checked when you submit.

18. Test question

A new straight-frontier comparison moves from (A,B)=(4,24) to (8,8). Give the positive B-per-A opportunity cost and reciprocal A-per-B rate. Use changes, not the endpoint ratio.

B forgone per A gained: v0. A forgone per B gained: v1.

19. What you can do now

You can turn a frontier into a rate in either direction and check it against a single step. Tell somebody why two jars a basket and half a basket a jar are the same sentence. Next: what it means when a place is not on its frontier at all.

Working for the steps left to you

10. Finish a directional slope check, step 3

4/8=0.5 A per B

The reciprocal answers a different directional question.